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How to Factor and Solve the 4x^2 + 13x + 10 Quadratic Expression Step by Step
Quadratic expressions are the cornerstone of intermediate algebra, forming the basis for higher-level mathematics, physics, and engineering. The expression 4x^2 + 13x + 10 is a classic example of a trinomial where the leading coefficient is greater than one. Understanding how to manipulate this specific expression requires a firm grasp of factoring techniques, the quadratic formula, and functional analysis.
This technical breakdown provides an exhaustive look at how to factor 4x^2 + 13x + 10, how to solve for its roots when set to zero, and how to interpret its behavior as a mathematical function.
Understanding the Components of 4x^2 + 13x + 10
Before diving into the calculations, it is essential to identify the structure of the expression. This is a quadratic expression in the standard form: ax^2 + bx + c
For the expression 4x^2 + 13x + 10:
- a (Leading Coefficient): 4
- b (Linear Coefficient): 13
- c (Constant Term): 10
Because the leading coefficient (a) is 4, this trinomial is slightly more complex to factor than those where a = 1. The positive signs throughout the expression indicate that any real roots or factors will involve additions rather than subtractions, simplifying the sign-tracking process.
Factoring 4x^2 + 13x + 10 Using the Splitting the Middle Term Method
The most efficient way to factor a quadratic of this type without resorting to the quadratic formula is the "AC Method," also known as splitting the middle term. This method relies on finding two numbers that satisfy specific product and sum requirements.
Step 1: Calculate the Product of a and c
Multiply the leading coefficient (a) by the constant term (c): 4 × 10 = 40
Step 2: Identify the Factor Pairs of 40
We need to find two numbers that multiply to 40 and add up to the middle coefficient (b), which is 13. Let’s examine the factor pairs of 40:
- 1 and 40 (Sum = 41)
- 2 and 20 (Sum = 22)
- 4 and 10 (Sum = 14)
- 5 and 8 (Sum = 13)
The pair that meets both criteria is 5 and 8.
Step 3: Rewrite the Middle Term
Using the pair found in Step 2, replace 13x with 5x and 8x: 4x^2 + 8x + 5x + 10
Note: The order (8x then 5x or 5x then 8x) does not matter for the final result, but placing 8x next to 4x often makes the grouping step more intuitive.
Step 4: Factor by Grouping
Divide the expression into two groups: (4x^2 + 8x) + (5x + 10)
Extract the greatest common factor (GCF) from each group:
- From (4x^2 + 8x), the GCF is 4x. This leaves: 4x(x + 2)
- From (5x + 10), the GCF is 5. This leaves: 5(x + 2)
Step 5: Final Factored Form
Since both terms share the common binomial factor (x + 2), we can factor it out: (4x + 5)(x + 2)
This is the fully factored version of the original expression.
Solving for Roots with the Quadratic Formula
When an expression is set to zero (4x^2 + 13x + 10 = 0), we seek the "roots" or "zeros"—the values of x that make the equation true. While factoring is fast, the Quadratic Formula is a universal tool that works even when factors are not easily identifiable integers.
The formula is: x = [-b ± √(b^2 - 4ac)] / 2a
Plugging in the Values
Using a = 4, b = 13, and c = 10: x = [-13 ± √(13^2 - 4(4)(10))] / 2(4)
Simplifying the Discriminant
First, calculate the value inside the square root (the discriminant): 13^2 = 169 4(4)(10) = 160 169 - 160 = 9
So, x = [-13 ± √9] / 8
Calculating the Final Values
Since √9 = 3: x = [-13 ± 3] / 8
This gives us two distinct solutions:
- x1 = (-13 + 3) / 8 = -10 / 8 = -1.25
- x2 = (-13 - 3) / 8 = -16 / 8 = -2
These roots match the factors derived earlier. Specifically, setting (4x + 5) = 0 yields x = -1.25, and setting (x + 2) = 0 yields x = -2.
Completing the Square for 4x^2 + 13x + 10
Completing the square is a method often used to derive the quadratic formula or to convert a quadratic into vertex form. Though more labor-intensive, it provides deep insight into the structure of the parabola.
- Set the equation to zero: 4x^2 + 13x + 10 = 0
- Isolate the constant: 4x^2 + 13x = -10
- Divide by the leading coefficient: Divide every term by 4 to make the x^2 coefficient 1. x^2 + (13/4)x = -2.5
- Find the "magic number": Take half of the x-coefficient (13/4 ÷ 2 = 13/8) and square it (169/64).
- Add the square to both sides: x^2 + (13/4)x + 169/64 = -2.5 + 169/64 x^2 + (13/4)x + 169/64 = -160/64 + 169/64 (x + 13/8)^2 = 9/64
- Solve for x: x + 13/8 = ±√(9/64) x + 13/8 = ±3/8 x = -13/8 ± 3/8
The results remain consistent: x = -10/8 (-1.25) and x = -16/8 (-2).
Analyzing the Parabolic Graph and Key Properties
If we treat y = 4x^2 + 13x + 10 as a function, we can describe its graph—a parabola.
Direction of Opening
Since the leading coefficient a = 4 is positive, the parabola opens upwards. This means the vertex represents the absolute minimum point of the function.
The Y-Intercept
The y-intercept occurs when x = 0. y = 4(0)^2 + 13(0) + 10 = 10 The graph crosses the y-axis at the point (0, 10).
Finding the Vertex
The x-coordinate of the vertex is found using the formula x = -b / 2a: x = -13 / (2 * 4) = -13 / 8 = -1.625
To find the y-coordinate, substitute -1.625 back into the original equation: y = 4(-1.625)^2 + 13(-1.625) + 10 y = 4(2.640625) - 21.125 + 10 y = 10.5625 - 21.125 + 10 = -0.5625
The vertex is located at (-1.625, -0.5625).
Axis of Symmetry
The axis of symmetry is the vertical line passing through the vertex: x = -1.625
Common Mistakes to Avoid When Working with Quadratics
When solving or factoring expressions like 4x^2 + 13x + 10, several common pitfalls can lead to incorrect answers.
- Sign Errors in the AC Method: Students often forget that if the product (ac) is positive and the sum (b) is positive, both factors must be positive. In this case, 5 and 8 are both positive. If the expression were 4x^2 - 13x + 10, both would need to be negative (-5 and -8).
- Incorrect GCF Extraction: During the grouping phase, it is vital to extract the largest possible factor. Forgetting the 'x' in 4x or failing to see that 10 is divisible by 5 can stall the process.
- Forgetting to Divide by 2a: In the quadratic formula, a common mistake is only dividing the radical part by 2a, rather than the entire numerator (-b ± radical).
- Misidentifying a, b, and c: Always ensure the equation is in standard form before identifying coefficients. If the equation were 4x^2 + 10 = -13x, you must move 13x to the left side first.
Practical Applications of Quadratic Equations
Why do we solve expressions like 4x^2 + 13x + 10? These equations model various real-world phenomena.
- Projectile Motion: The path of an object thrown into the air follows a quadratic curve. The roots represent the time when the object hits the ground.
- Business Optimization: Quadratic equations can model profit margins where "x" represents the price of a product. Finding the vertex allows a company to find the price that maximizes profit.
- Area Problems: If a rectangular garden has dimensions related to x, the total area is often a quadratic expression. Factoring helps find the possible dimensions of the garden given a specific area.
Summary
The quadratic expression 4x^2 + 13x + 10 is a manageable yet comprehensive example of algebraic factoring and solving. By using the AC method, we determined its factored form to be (4x + 5)(x + 2). Through the quadratic formula and completing the square, we confirmed its roots at x = -1.25 and x = -2. Graphically, it represents an upward-opening parabola with a vertex at (-1.625, -0.5625) and a y-intercept at 10. Mastery of these techniques ensures a strong foundation for tackling more complex mathematical challenges.
FAQ
How do you factor 4x^2 + 13x + 10? It is factored by splitting the middle term 13x into 8x and 5x, resulting in the form 4x(x + 2) + 5(x + 2), which simplifies to (4x + 5)(x + 2).
What are the zeros of 4x^2 + 13x + 10? The zeros (or roots) are x = -1.25 and x = -2. These are the points where the graph of the function intersects the x-axis.
Can this expression be factored if the signs were different? Yes, but the factors would change. For example, 4x^2 - 13x + 10 would factor into (4x - 5)(x - 2), as we would need two negative numbers that multiply to 40 and add to -13.
Is 4x^2 + 13x + 10 a perfect square trinomial? No. A perfect square trinomial follows the pattern a^2 + 2ab + b^2. For this expression to be a perfect square starting with 4x^2 (which is (2x)^2) and ending with 10, the constant would need to be a perfect square like 9 or 16, and the middle term would need to match the 2ab pattern.
What is the discriminant of 4x^2 + 13x + 10? The discriminant (D = b^2 - 4ac) is 9. Since the discriminant is a positive perfect square, the equation has two distinct, rational real roots.
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